Question

26
find the missing side. round to the nearest tenth.
(refer to your notes on sohcahtoa.)

Explanation:

Step1: Identify trigonometric ratio

We have a right triangle with opposite side to \(62^\circ\) as \(11\) and hypotenuse as \(x\). So we use \(\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}\), so \(\sin(62^\circ)=\frac{11}{x}\).

Step2: Solve for \(x\)

Rearrange the equation: \(x = \frac{11}{\sin(62^\circ)}\). Calculate \(\sin(62^\circ)\approx0.8829\), then \(x=\frac{11}{0.8829}\approx12.5\).

Answer:

Equation: \(\sin(62^\circ)=\frac{11}{x}\)
\(x = 12.5\)