Question

1. - / 1 points 0/12 submissions used

marcella leaves home at 9:00 a.m. and drives to school, arriving at 9:45 a.m. if the distance between home and school is 24 mi, what is marcellas average rate of speed?
mph

1. - / 1 points 0/12 submissions used

the ride for health bicycle club has chosen a 52 - mile course for this saturdays ride. if the riders plan on averaging 13 mph while they are riding, and they have a 1 - hour lunch break planned, how long will it take them to complete the trip?
hr

Explanation:

Step1: Calculate time taken for Marcella's drive

Marcella leaves at 9:00 a.m. and arrives at 9:45 a.m. The time taken \(t_1\) is \(45\) minutes. Convert minutes to hours: \(t_1=\frac{45}{60}=\frac{3}{4}\text{ h}\)
The distance \(d_1 = 24\) mi. Using the formula \(v=\frac{d}{t}\), where \(v\) is speed, \(d\) is distance and \(t\) is time.
\(v_1=\frac{24}{\frac{3}{4}}\)

$$v_1=24\times\frac{4}{3}=32\text{ mph}$$

Step2: Calculate time for bicycle - club's riding time

The distance for the bicycle - club \(d_2 = 52\) miles and their riding speed \(v_2=13\) mph. Using the formula \(t=\frac{d}{v}\), the riding time \(t_{riding}=\frac{52}{13} = 4\) h.
They have a 1 - hour lunch break. So the total time \(t_{total}=t_{riding}+t_{lunch}\)
\(t_{total}=4 + 1=5\) h

Answer:

Marcella's average rate of speed is \(32\) mph. The time for the bicycle - club to complete the trip is \(5\) h.