Question

23 a crate is pulled forward with 200 n of force, which results in the crate maintaining a constant velocity of 5 m/s. what is the frictional force acting on the crate? a 200 n b 1,000 n c 40 n d 500 n

Explanation:

Step1: Analyze the motion state

The crate is moving at a constant velocity. According to Newton's first law, when an object is in a state of uniform motion (constant velocity), the net force acting on it is zero.

Step2: Determine the relationship between pulling force and frictional force

Let the pulling force be \(F = 200\space N\) and the frictional force be \(f\). Since the net force \(F_{net}=F - f=0\) (because \(F_{net} = ma\) and \(a = 0\) for constant - velocity motion).
Then \(f=F\).

Answer:

A. \(200\space N\)