triangle classification theorems signment active creating an acute tria…
14
14
triangle classification theorems
signment active
creating an acute triangle
which value from the list below, when substituted for x, would represent an acute triangle with side lengths x, x+4, and 20? assume that the longest side of the triangle is of length 20 units.
○ 8
○ 10
○ 12
○ 14
triangle classification theorems
signment active
creating an acute triangle
which value from the list below, when substituted for x, would represent an acute triangle with side lengths x, x+4, and 20? assume that the longest side of the triangle is of length 20 units.
○ 8
○ 10
○ 12
○ 14
For an acute triangle with longest side $c$, $a^2 + b^2 > c^2$. Here $c=20$, $a=x$, $b=x+4$.
$x^2 + (x+4)^2 > 20^2$
Expand: $x^2 + x^2 + 8x + 16 > 400$
Simplify: $2x^2 + 8x - 384 > 0$
Divide by 2: $x^2 + 4x - 192 > 0$
Factor: $(x+16)(x-12) > 0$
Since side length is positive, $x > 12$.
Also, $x + (x+4) > 20$ → $2x + 4 > 20$ → $x > 8$. Combine with $x>12$.
Check options: only 14 satisfies $x>12$.
14
For an acute triangle with longest side $c$, $a^2 + b^2 > c^2$. Here $c=20$, $a=x$, $b=x+4$.
$x^2 + (x+4)^2 > 20^2$
Expand: $x^2 + x^2 + 8x + 16 > 400$
Simplify: $2x^2 + 8x - 384 > 0$
Divide by 2: $x^2 + 4x - 192 > 0$
Factor: $(x+16)(x-12) > 0$
Since side length is positive, $x > 12$.
Also, $x + (x+4) > 20$ → $2x + 4 > 20$ → $x > 8$. Combine with $x>12$.
Check options: only 14 satisfies $x>12$.
14
triangle classification theorems signment active creating an acute triangle which value from the list below, when substituted for x, would represent an acute triangle with side lengths x, x+4, and 20? assume that the longest side of the triangle is of length 20 units. ○ 8 ○ 10 ○ 12 ○ 14
Top-left cell: 180 Top-right cell: 6 Bottom-left cell: 600 Bottom-right cell: 20 Final product: 806
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