1) $x^{2}+20x+100$ $(x+10)^2$ 3) $2n^{3}-18n^{2}+28n$
1) $\boldsymbol{(x+10)^2}$ 3) $\boldsymbol{2n(n-2)(n-7)}$
Question
- $x^{2}+20x+100$
$(x+10)^2$
- $2n^{3}-18n^{2}+28n$
Solution Steps
-
Understand the question
- $x^{2}+20x+100$
$(x+10)^2$
- $2n^{3}-18n^{2}+28n$
-
Explanation
Step1: Factor perfect square trinomial
$x^2 + 20x + 100 = (x+10)^2$
Step2: Factor out GCF from cubic
$2n^3 - 18n^2 + 28n = 2n(n^2 - 9n + 14)$
Step3: Factor quadratic trinomial
$n^2 - 9n + 14 = (n-2)(n-7)$
Step4: Combine all factors
$2n(n-2)(n-7)$
-
Final answer
- $\boldsymbol{(x+10)^2}$
- $\boldsymbol{2n(n-2)(n-7)}$
Answer
Explanation
Step1: Factor perfect square trinomial
$x^2 + 20x + 100 = (x+10)^2$
Step2: Factor out GCF from cubic
$2n^3 - 18n^2 + 28n = 2n(n^2 - 9n + 14)$
Step3: Factor quadratic trinomial
$n^2 - 9n + 14 = (n-2)(n-7)$
Step4: Combine all factors
$2n(n-2)(n-7)$
Answer
- $\boldsymbol{(x+10)^2}$
- $\boldsymbol{2n(n-2)(n-7)}$
Question Image
Click to enlargeQuestion Analysis
Subject
mathematics
Sub Subject
algebra
Education Level
high school
Difficulty
unspecified
Question Type
calculation
Multi Question
No
Question Count
1
Analysis Status
completed
Analyzed At
2026-02-09T20:12:46
OCR Text
Show OCR extraction
1) $x^{2}+20x+100$
$(x+10)^2$
3) $2n^{3}-18n^{2}+28n$
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