QUESTION IMAGE
Question
- what is the height of cylinder pictured below? 5 in. 13 in. 8 in 144 in 12 in 54 in
Step1: Identify the right triangle
The diameter of the base (5 in) and the height of the cylinder form the legs of a right triangle, with the diagonal (13 in) as the hypotenuse.
Step2: Apply Pythagorean theorem
Let \( h \) be the height. The diameter is 5 in, so the radius - related leg is 5 in? Wait, no, the diameter is 5 in, so one leg (let's say \( a = 5 \)) and the height \( h \) (leg \( b \)) and hypotenuse \( c=13 \). By Pythagorean theorem \( a^{2}+b^{2}=c^{2} \), so \( 5^{2}+h^{2}=13^{2} \).
Step3: Solve for h
\( 25 + h^{2}=169 \), then \( h^{2}=169 - 25=144 \), so \( h = \sqrt{144}=12 \) in.
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12 in (corresponding to the option "12 in")