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Question
5/20 if three sides of a right triangle are 9, 40, and 41, which side is the hypotenuse? 41 40 9
Step1: Recall Pythagorean theorem
$$a^{2}+b^{2}=c^{2}$$ (where \(c\) is hypotenuse)
Step2: Calculate \(9^{2}+40^{2}\)
$$9^{2}+40^{2}=81 + 1600=1681$$
Step3: Calculate \(41^{2}\)
$$41^{2}=1681$$
Since \(9^{2}+40^{2}=41^{2}\), by Pythagorean theorem, 41 is the hypotenuse.
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