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#20 find the degree of the monomial. $s^6t$ the degree is \\(\\square\\…

Question

#20
find the degree of the monomial.
$s^6t$
the degree is \\(\square\\).

Explanation:

Step1: Recall the definition of the degree of a monomial

The degree of a monomial is the sum of the exponents of all its variables.

Step2: Identify the exponents of the variables in the monomial \( s^{5}t \)

For the variable \( s \), the exponent is \( 5 \). For the variable \( t \), since there is no visible exponent, it is understood to be \( 1 \) (because \( t = t^{1} \)).

Step3: Calculate the sum of the exponents

To find the degree, we add the exponents of \( s \) and \( t \). So we calculate \( 5 + 1 \).
\( 5+1 = 6 \)

Answer:

\( 6 \)