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1st attempt part 1 (1 point) what is the atoms change in energy as a re…

Question

1st attempt
part 1 (1 point)
what is the atoms change in energy as a result of this transition?
j
part 2 (1 point)
what is the wavelength of radiation corresponding to this transition?
m
part 3 (1 point)
what one kind of telescope would astronomers need in order to detect radiation of this wavelength?
choose one or more:
visible
radio
infrared
microwave

Explanation:

Step1: Recall energy - wavelength relation

The energy change of an atom during a transition is given by $\Delta E = h
u$, where $h = 6.626\times10^{- 34}\text{ J}\cdot\text{s}$ is Planck's constant and $
u$ is the frequency of the radiation. Also, $c=\lambda
u$, so $
u=\frac{c}{\lambda}$, and $\Delta E=\frac{hc}{\lambda}$. However, since no information about the transition levels (to calculate $\Delta E$ from energy - level differences) or wavelength/frequency is given initially, we assume we need to use general formulas. If we know the energy - level difference $\Delta E = E_2 - E_1$ for the transition of an electron in an atom, we can calculate the energy change. But without specific level information, if we are given frequency $
u$, then $\Delta E=h
u$.

Step2: Calculate wavelength from energy

If we know the energy change $\Delta E$, we can find the wavelength $\lambda$ using $\lambda=\frac{hc}{\Delta E}$.

Step3: Determine telescope type

Visible light has wavelengths in the range of approximately $400 - 700\text{ nm}(400\times10^{-9}-700\times10^{-9}\text{ m})$, radio waves have wavelengths from about 1 mm to 100 km, infrared has wavelengths from about $700\text{ nm}$ to 1 mm, and microwaves have wavelengths from about 1 mm - 30 cm. Based on the calculated wavelength in Part 2, we can determine the type of telescope.

Since no specific values for the transition are given in the problem statement, we cannot provide numerical answers. But the general approach is as above.

Answer:

Part 1: Without specific transition - level or frequency information, cannot be determined.
Part 2: Without energy - change or frequency information, cannot be determined.
Part 3: Depends on the wavelength calculated in Part 2. If $\lambda$ is in the visible range ($400 - 700\text{ nm}$), visible telescope; if in the radio - wave range (1 mm - 100 km), radio telescope; if in the infrared range ($700\text{ nm}-1\text{ mm}$), infrared telescope; if in the microwave range (1 mm - 30 cm), microwave telescope.