Question

1. find the perimeter and area of this triangle.

11 yd
28 yd

Explanation:

Step1: Identify Triangle Type

The triangle is right - angled (from the diagram, right angle between 11 yd and 28 yd sides). Let \(a = 11\) yd, \(b = 28\) yd. First, find the hypotenuse \(c\) using Pythagorean theorem \(c=\sqrt{a^{2}+b^{2}}\).
\(c=\sqrt{11^{2}+28^{2}}=\sqrt{121 + 784}=\sqrt{905}\approx30.08\) yd.

Step2: Calculate Perimeter

Perimeter \(P=a + b + c\). Substitute \(a = 11\), \(b = 28\), \(c\approx30.08\).
\(P=11 + 28+30.08 = 69.08\) yd.

Step3: Calculate Area

For a right - angled triangle, area \(A=\frac{1}{2}\times base\times height\). Here, base \(b = 28\) yd, height \(a = 11\) yd.
\(A=\frac{1}{2}\times28\times11=14\times11 = 154\) square yards.

Answer:

Perimeter \(\approx69.08\) yd, Area \( = 154\) square yards.