Question

18 essay 1 point what is the kinetic energy of a 0.145 kg baseball moving at 42 m/s? edit format table 12pt paragraph b i u a t²

Explanation:

Step1: Recall the kinetic energy formula

The formula for kinetic energy is \(K = \frac{1}{2}mv^{2}\), where \(m\) is the mass and \(v\) is the velocity.

Step2: Substitute the given values

Given \(m = 0.145\space kg\) and \(v = 42\space m/s\). Substitute into the formula: \(K=\frac{1}{2}\times0.145\times(42)^{2}\).
First, calculate \((42)^{2}=42\times42 = 1764\).
Then, \(\frac{1}{2}\times0.145\times1764= 0.0725\times1764\).

Step3: Perform the multiplication

\(0.0725\times1764 = 128.82\space J\)

Answer:

The kinetic energy of the baseball is \(128.82\space J\)