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Question
- the pet kennel has 12 dogs and cats for the weekend. the number of dogs is three less than twice the number of cats. write a system of equations to model this.\\(\
$$\begin{cases} d + c = 12 \\\\ c = 2d - 3 \\end{cases}$$
\\)\\(\
$$\begin{cases} d + c = 12 \\\\ 2c = d - 3 \\end{cases}$$
\\)\\(\
$$\begin{cases} d + c = 12 \\\\ d = 3 - 2c \\end{cases}$$
\\)\\(\
$$\begin{cases} d + c = 12 \\\\ d = 2c - 3 \\end{cases}$$
\\)
Step1: Define total pets equation
Let $d$ = number of dogs, $c$ = number of cats. Total pets: $d + c = 12$
Step2: Define dog-cat relationship equation
Dogs = 2×cats - 3: $d = 2c - 3$
Step3: Match to option
Pair equations into a system:
$$\begin{cases} d + c = 12 \\ d = 2c - 3 \end{cases}$$
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$\boldsymbol{
$$\begin{cases} d + c = 12 \\ d = 2c - 3 \end{cases}$$
}$ (the fourth option)