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Question
- factor. 9a² - 16
- what does it mean when (x³ + 2x² - 12x - 24)÷(x + 2) has a remainder of zero?
16. Factor $9a^{2}-16$
Step1: Recognize difference - of - squares
The expression $9a^{2}-16$ is in the form $x^{2}-y^{2}$, where $x = 3a$ and $y = 4$ since $(3a)^{2}=9a^{2}$ and $4^{2}=16$.
Step2: Apply difference - of - squares formula
The formula for factoring $x^{2}-y^{2}$ is $(x + y)(x - y)$. Substituting $x = 3a$ and $y = 4$, we get $(3a+4)(3a - 4)$.
According to the factor theorem, if $f(x)$ is a polynomial and $f(c)=0$ when $f(x)$ is divided by $(x - c)$, then $(x - c)$ is a factor of $f(x)$. Here, when dividing the polynomial $x^{3}+2x^{2}-12x - 24$ by $(x + 2)$ (equivalent to $(x-(-2))$) and getting a remainder of zero, it means that $x=-2$ is a root of the polynomial $x^{3}+2x^{2}-12x - 24$, and $(x + 2)$ is a factor of the polynomial $x^{3}+2x^{2}-12x - 24$.
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$(3a + 4)(3a-4)$