Question

a 1520 kg car in motion rolls down a frictionless hill that is inclined at (14.4^{circ}).

what is the acceleration of the car?

(a = ?\text{ m/s}^2)

Explanation:

⚡ Using what you learned: newton's laws of motion

Step 1: Identify forces along the incline

$$ F_{\text{net}} = m g \sin(\theta) $$

Step 2: Calculate acceleration

$$ a = \frac{F_{\text{net}}}{m} = g \sin(\theta) $$

$$ a = 9.8 \cdot \sin(14.4^\circ) $$

$$ a \approx 9.8 \cdot 0.2487 \approx 2.44 \text{ m/s}^2 $$

Answer:

2.44