Question

14 multiple choice 1.5 points suppose that a dominant mutation in humans is designated d. if a heterozygous male with this mutation is married to a normal female, whats the chance for the couple to have a baby with this mutation? one quarter one half three quarters 100% previous next

Explanation:

Step1: Determine genotypes

The heterozygous male has genotype Dd and the normal female has genotype dd.

Step2: Set up Punnett - square cross

	D	d
d	Dd	dd

Step3: Calculate probability

Out of 4 possible genotypes of offspring, 2 are Dd (with the mutation) and 2 are dd (without the mutation). The probability of having a baby with the mutation (genotype Dd) is $\frac{2}{4}=\frac{1}{2}$.

Answer:

B. one half