Question

1. the figure below shows square rstu on a coordinate plane. if the square is dilated using the rule (x, y)→(1/2x, 1/2y) with the origin as the center of dilation, what are the coordinates of vertex s of the dilated square rstu? a (6, 24) c (6, 8) b (3/2, 6) d (1/2, 3)

Explanation:

Step1: Identify the coordinates of point S

From the graph, the coordinates of point S are (3, 12).

Step2: Apply the dilation rule

The dilation rule is $(x,y)\to(\frac{1}{2}x,\frac{1}{2}y)$. For point S with $x = 3$ and $y=12$, we have $\frac{1}{2}x=\frac{1}{2}\times3=\frac{3}{2}$ and $\frac{1}{2}y=\frac{1}{2}\times12 = 6$.

Answer:

B. $(\frac{3}{2},6)$