Question

1. a 0.135 kg ball is tossed upward from a height of 1.20 m above the ground with an initial speed of 15.0 m/s. what is the balls total mechanical energy at the moment it is tossed upward? (1 point)

1.59 j
16.8 j
13.6 j
15.2 j

Explanation:

Step1: Calculate kinetic energy

The formula for kinetic energy is \(K = \frac{1}{2}mv^{2}\).
Given \(m = 0.135\space kg\) and \(v=15.0\space m/s\), then \(K=\frac{1}{2}\times0.135\times(15.0)^{2}=\frac{1}{2}\times0.135\times225 = 15.1875\space J\)

Step2: Calculate potential energy

The formula for gravitational potential energy is \(U = mgh\).
Given \(m = 0.135\space kg\), \(g = 9.8\space m/s^{2}\), and \(h = 1.20\space m\), then \(U=0.135\times9.8\times1.20=1.5876\space J\)

Step3: Calculate total mechanical energy

The total mechanical energy \(E=K + U\).
\(E=15.1875+ 1.5876=16.7751\approx16.8\space J\)

Answer:

16.8 J