Question

1. which of the circuits will have the brighter bulb (\6v\ means one 6-volt battery)?

6v
6v 6v
a b
a
b

Explanation:

Step1: Analyze Voltage in Each Circuit

In Circuit A, there is one 6V battery, so the total voltage across the bulb is \( V_A = 6V \).
In Circuit B, two 6V batteries are connected in series (positive to negative), so the total voltage is \( V_B = 6V + 6V = 12V \).

Step2: Relate Voltage to Bulb Brightness

The brightness of a bulb is related to the power it dissipates, \( P = \frac{V^2}{R} \) (where \( R \) is the bulb’s resistance, assumed constant). Since \( V_B > V_A \), the power \( P_B > P_A \). A higher power means a brighter bulb.

Answer:

B