QUESTION IMAGE
Question
- a) hexagonal pyramid b) trapezoidal prism c) cone d) square prism
- a) cylinder b) rectangular prism c) triangular prism d) pentagonal prism
find the volume of each figure. round your answers to the nearest hundredth, if necessary.
- a) 48.18 mi³ b) 33.51 mi³ c) 35.81 mi³ d) 268.08 mi³
- a) 772.54 in³ b) 637.61 in³ c) 633.36 in³ d) 775.73 in³
- a) 53 cm³ b) 147 cm³ c) 72 cm³ d) 49 cm³
- a) 24 cm³ b) 16 cm³ c) 13 cm³ d) 27 cm³
- a) 115.78 km³ b) 560 km³ c) 171.14 km³ d) 186.67 km³
- a) 91 km³ b) 42 km³ c) 80 km³ d) 73 km³
Step1: Recall volume formulas
Volume of sphere $V = \frac{4}{3}\pi r^{3}$, volume of pyramid $V=\frac{1}{3}Bh$ (where $B$ is base - area and $h$ is height), volume of prism $V = Bh$.
Step2: Solve for problem 15
Given sphere with $r = 4$ mi. $V=\frac{4}{3}\pi r^{3}=\frac{4}{3}\pi(4)^{3}=\frac{4}{3}\pi\times64=\frac{256\pi}{3}\approx268.08$ mi³.
Step3: Solve for problem 16
Given sphere with $r = 5.7$ in. $V=\frac{4}{3}\pi r^{3}=\frac{4}{3}\pi(5.7)^{3}=\frac{4}{3}\pi\times185.193\approx772.54$ in³.
Step4: Solve for problem 17
For the pyramid with base dimensions $3$ cm and $7$ cm and height $7$ cm. Base - area $B = 3\times7 = 21$ cm². $V=\frac{1}{3}Bh=\frac{1}{3}\times21\times7 = 49$ cm³.
Step5: Solve for problem 18
For the triangular prism with base triangle having sides $3$ cm, $4$ cm, $5$ cm (right - triangle with base $b = 3$ cm and height $h = 4$ cm) and length $l = 4$ cm. Base - area of triangle $B=\frac{1}{2}\times3\times4 = 6$ cm². $V=Bh=6\times4 = 24$ cm³.
Step6: Solve for problem 19
For the pyramid with base dimensions $7$ km and $8$ km and height $10$ km. Base - area $B = 7\times8=56$ km². $V=\frac{1}{3}Bh=\frac{1}{3}\times56\times10=\frac{560}{3}\approx186.67$ km³.
Step7: Solve for problem 20
For the rectangular prism with dimensions $4$ km, $4$ km, and $5$ km. $V = l\times w\times h=4\times4\times5 = 80$ km³.
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- D. 268.08 mi³
- A. 772.54 in³
- D. 49 cm³
- A. 24 cm³
- D. 186.67 km³
- C. 80 km³