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13 find the m∠vwy. (7x + 2)° (4x + 23)°

Question

13 find the m∠vwy. (7x + 2)° (4x + 23)°

Explanation:

Step1: Use vertical angles property

Vertical angles are equal. So, \(7x + 2=4x + 23\).

Step2: Solve for \(x\)

Subtract \(4x\) from both sides: \(7x-4x + 2=4x-4x + 23\), which gives \(3x+2 = 23\).
Subtract \(2\) from both sides: \(3x+2 - 2=23 - 2\), so \(3x=21\).
Divide both sides by \(3\): \(x=\frac{21}{3}=7\).

Step3: Find \(m\angle VWY\)

Since \(m\angle VWY=(7x + 2)^{\circ}\), substitute \(x = 7\).
\(m\angle VWY=(7\times7 + 2)^{\circ}=(49+2)^{\circ}=51^{\circ}\).

Answer:

\(51^{\circ}\)