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13 essay 1 point in a tug - of - war, each side pulls with a force of 5…

Question

13 essay 1 point in a tug - of - war, each side pulls with a force of 500 newtons, but the rope does not move. how much work is done? edit format table 12pt paragraph b i u a t³

Explanation:

Step1: Recall the work formula

The formula for work is \(W = F\times d\times\cos\theta\), where \(F\) is the force, \(d\) is the displacement, and \(\theta\) is the angle between the force and the displacement.

Step2: Analyze the displacement

In this case, the rope does not move, so \(d = 0\) meters.

Step3: Calculate the work

Substitute \(d = 0\) into the work formula: \(W=500\times0\times\cos\theta = 0\) (since \(\cos\theta\) is just a multiplier between - 1 and 1, multiplying by 0 still gives 0).

Answer:

The work done is \(0\) joules.