Question

1. $-x-6+(x^{2}y)^{2}-2x+4y$

extra credit (3 points)
literal problems
determine the literal - value answers for these problems.

1. the total voltage ($e_t$), in volts, of the circuit shown in figure 13 - 35 is represented as $x$. the amount of voltage taken by 5 of the 6 resistors is given as $e_{r_1}$ through $e_{r_5}$.

figure 13 - 35
details
6 resistances $r$ sub 1 to $r$ sub 6 are connected in series. the voltage across each resistance is as follows. $e$ sub $r$ sub $1 = 0.10x$. $e$ sub $r$ sub $2 = 0.15x$. $e$ sub $r$ sub $3 = 0.20x$. $e$ sub $r$ sub $4 = 0.12x$. $e$ sub $r$ sub $5 = 0.18x$. $e$ sub $r$ sub $6 =$ question point. the total voltage $e$ sub $t = x$.
a. what is the sum of the voltage taken by $r_1$, $r_2$, $r_3$, $r_4$, and $r_5$?

Explanation:

Step1: Identify given voltages

We are given $E_{R_1}=0.10x$, $E_{R_2}=0.15x$, $E_{R_3}=0.20x$, $E_{R_4}=0.12x$, $E_{R_5}=0.18x$.

Step2: Calculate sum of voltages

Sum $S = E_{R_1}+E_{R_2}+E_{R_3}+E_{R_4}+E_{R_5}$.
Substitute the values: $S=(0.10x + 0.15x+0.20x + 0.12x+0.18x)$.
Combine like - terms: $S=(0.10 + 0.15+0.20 + 0.12+0.18)x$.
$0.10 + 0.15+0.20 + 0.12+0.18 = 0.75$. So $S = 0.75x$.

Answer:

$0.75x$