Question

1. a walkman uses four standard 1.5 v batteries. how much resistance is in the circuit if it uses a current of 0.02a? v= i= r=

Explanation:

Step1: Calculate the total voltage

The walkman uses four \(1.5\) V batteries. When batteries are in series, the total voltage \(V\) is the sum of the individual battery voltages. So \(V = 4\times1.5\space V=6\space V\).

Step2: Use Ohm's law to find resistance

Ohm's law is \(V = IR\), where \(V\) is voltage, \(I\) is current, and \(R\) is resistance. We need to solve for \(R\), so \(R=\frac{V}{I}\). Given \(V = 6\space V\) and \(I=0.02\space A\), then \(R=\frac{6}{0.02}\space\Omega\).

Answer:

\(300\space\Omega\)