Question

12 charity is sledding down a snowy hill. when she begins her slide at the top of the hill, she has a velocity of 2.2 m/s north. she slides down the hill for 4.1 seconds, and when she reaches the bottom, she has a velocity of 5.9 m/s. how far did charity sled during this 4.1 - second period?
17 meters
33 meters
4.5 meters
12 meters

Explanation:

Step1: Find the average velocity

The formula for average velocity \(v_{avg}=\frac{v_{i} + v_{f}}{2}\), where \(v_{i} = 2.2\ m/s\) (initial velocity) and \(v_{f}=5.9\ m/s\) (final velocity).
\(v_{avg}=\frac{2.2 + 5.9}{2}=\frac{8.1}{2}=4.05\ m/s\)

Step2: Calculate the distance

The formula for distance \(d=v_{avg}\times t\), where \(t = 4.1\ s\) (time).
\(d=4.05\times4.1 = 16.605\approx17\ m\)

Answer:

17 meters