Question

q 11. the factored form of ( x^3 - 3x^2 - 11x + 33 ) is - choose the correct answer - (x - 2)(x + 2)(x - 3) (x - 3)(x^2 - 11) (x - 1)(x + 3)(x - 11) (x + 3)(x + 11)(x - 33)

Explanation:

Step1: Group terms

Group the polynomial \(x^3 - 3x^2 - 11x + 33\) as \((x^3 - 3x^2) + (-11x + 33)\).

Step2: Factor each group

Factor \(x^2\) from the first group: \(x^2(x - 3)\). Factor \(-11\) from the second group: \(-11(x - 3)\).

Step3: Factor out common binomial

Now we have \(x^2(x - 3)-11(x - 3)\). Factor out \((x - 3)\) to get \((x - 3)(x^2 - 11)\).

Answer:

\((x - 3)(x^2 - 11)\) (the second option: \((x - 3)(x^2 - 11)\))