Question

1. what is the resistance of a circuit with three 1.5v batteries and running at a current of 5a? v= i= r=

Explanation:

Step1: Calculate the total voltage

When batteries are in series, the total voltage \(V\) is the sum of the individual voltages. Here, each battery has a voltage of \(1.5\space V\) and there are \(n = 3\) batteries. So, \(V=n\times1.5\space V\).
\(V = 3\times1.5\space V=4.5\space V\)

Step2: Use Ohm's law to find resistance

Ohm's law is given by \(V = IR\), where \(I\) is the current and \(R\) is the resistance. We need to solve for \(R\), so \(R=\frac{V}{I}\).
Given \(I = 5\space A\) and \(V = 4.5\space V\), then \(R=\frac{4.5\space V}{5\space A}\)
\(R = 0.9\space\Omega\)

Answer:

\(V = 4.5\space V\), \(I = 5\space A\), \(R=0.9\space\Omega\)