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a 10.5 kg rock sits on the edge of a 23.8 - m cliff. calculate its gpe …

Question

a 10.5 kg rock sits on the edge of a 23.8 - m cliff. calculate its gpe relative to the ground below.

Explanation:

Step1: Identify the formula

The formula for gravitational potential energy (GPE) is \(GPE = m\times g\times h\), where \(m\) is mass, \(g = 9.8\ m/s^{2}\) (acceleration due to gravity), and \(h\) is height.

Step2: Substitute the values

Given \(m = 10.5\ kg\), \(h=23.8\ m\), and \(g = 9.8\ m/s^{2}\).
\(GPE=10.5\times9.8\times23.8\)
First, calculate \(10.5\times9.8 = 102.9\)
Then, \(102.9\times23.8=2449.02\)

Answer:

\(2449.02\ J\)