Question

1. a 5 kg bowling ball is rolled down the bowling alley lane. the ball accelerates at 1.88 m/s^2. if the force of sliding friction between the ball and the lane is 7.35 n, what was the force applied to the bowling ball?

Explanation:

Step1: Apply Newton's second law

Newton's second law is $F_{net}=ma$. The net force $F_{net}$ is the applied force $F_{applied}$ minus the frictional force $F_f$. So, $F_{net}=F_{applied}-F_f$.

Step2: Rearrange the formula to solve for $F_{applied}$

From $F_{applied}-F_f = ma$, we can get $F_{applied}=ma + F_f$.

Step3: Substitute the given values

Given $m = 5\,\text{kg}$, $a=1.88\,\text{m/s}^2$, and $F_f = 7.35\,\text{N}$.
First, calculate $ma$: $ma=5\times1.88 = 9.4\,\text{N}$.
Then, $F_{applied}=9.4+7.35$.

Step4: Calculate the final result

$F_{applied}=16.75\,\text{N}$.

Answer:

$16.75\,\text{N}$