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Question
- donovan has at most 25 colored blocks in his bag. the number of green blocks is at least 10 more than the number of orange blocks. which statement is not a viable solution to this scenario? you can use the graph to help you. graph of number of green blocks vs number of orange blocks view image description he has 4 orange blocks and 18 green blocks. he has 2 orange blocks and 20 green blocks. he has -1 orange blocks and 16 green blocks. he has 3 orange blocks and 18 green blocks.
Step1: Analyze the constraints
Let \( o \) be the number of orange blocks and \( g \) be the number of green blocks. The constraints are:
- \( o + g \leq 25 \) (at most 25 colored blocks)
- \( g \geq o + 10 \) (green blocks at least 10 more than orange)
- \( o \geq 0 \) (number of blocks can't be negative)
Step2: Check each option
- Option 1: 4 orange, 18 green
Check \( o + g = 4 + 18 = 22 \leq 25 \) and \( 18 \geq 4 + 10 = 14 \). Both hold. Viable.
- Option 2: 2 orange, 20 green
Check \( o + g = 2 + 20 = 22 \leq 25 \) and \( 20 \geq 2 + 10 = 12 \). Both hold. Viable.
- Option 3: -1 orange, 16 green
\( o = -1 \) is invalid (number of blocks can't be negative). Not viable.
- Option 4: 3 orange, 18 green
Check \( o + g = 3 + 18 = 21 \leq 25 \) and \( 18 \geq 3 + 10 = 13 \). Both hold. Viable.
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He has -1 orange blocks and 16 green blocks.