Question

at 10:17 a.m., you pass a police car at 55mph that is stopped on the freeway. you pass a second police car at 55mph at 10:53 a.m., which is located 39 miles from the first police car. if the speed limit is 70mph, can the police cite you for speeding?

find your average velocity from the 10:17 a.m. to 10:53 a.m.

mph
round value above to 2 decimal places.

by the mvt, since the average velocity over the interval was select an answer than the posted speed limit of 70mph the police select an answer site you for speeding.

Explanation:

Step1: Calculate time elapsed

From 10:17 a.m. to 10:53 a.m., the time elapsed is \( 53 - 17 = 36 \) minutes. Convert minutes to hours: \( \frac{36}{60} = 0.6 \) hours.

Step2: Calculate average velocity

Average velocity \( v_{avg} = \frac{\text{distance}}{\text{time}} \). Distance is 39 miles, time is 0.6 hours. So \( v_{avg} = \frac{39}{0.6} = 65.00 \) mph.

Step3: Compare with speed limit

65 mph is less than 70 mph. By MVT, if average velocity is less than speed limit, police cannot cite for speeding.

Answer:

Average velocity: 65.00 mph
First select: less
Second select: cannot