Question

4）$7\frac{4}{9} = \underline{\quad\quad}$
7）$5\frac{1}{8} = \underline{\quad\quad}$
10）$5\frac{7}{10} = \underline{\quad\quad}$
13）$2\frac{5}{7} = \underline{\quad\quad}$

Explanation:

To solve these problems, we need to convert mixed numbers to improper fractions. The formula to convert a mixed number \( a\frac{b}{c} \) to an improper fraction is \( \frac{a \times c + b}{c} \).

Problem 4: \( 7\frac{4}{9} \)

Step 1: Apply the formula

Here, \( a = 7 \), \( b = 4 \), and \( c = 9 \). So we calculate \( 7 \times 9 + 4 \) for the numerator.
\( 7 \times 9 + 4 = 63 + 4 = 67 \)
The denominator remains \( 9 \).
So, \( 7\frac{4}{9} = \frac{67}{9} \)

Problem 7: \( 5\frac{1}{8} \)

Step 1: Apply the formula

Here, \( a = 5 \), \( b = 1 \), and \( c = 8 \). So we calculate \( 5 \times 8 + 1 \) for the numerator.
\( 5 \times 8 + 1 = 40 + 1 = 41 \)
The denominator remains \( 8 \).
So, \( 5\frac{1}{8} = \frac{41}{8} \)

Problem 10: \( 5\frac{7}{10} \)

Step 1: Apply the formula

Here, \( a = 5 \), \( b = 7 \), and \( c = 10 \). So we calculate \( 5 \times 10 + 7 \) for the numerator.
\( 5 \times 10 + 7 = 50 + 7 = 57 \)
The denominator remains \( 10 \).
So, \( 5\frac{7}{10} = \frac{57}{10} \)

Problem 13: \( 2\frac{5}{7} \)

Step 1: Apply the formula

Here, \( a = 2 \), \( b = 5 \), and \( c = 7 \). So we calculate \( 2 \times 7 + 5 \) for the numerator.
\( 2 \times 7 + 5 = 14 + 5 = 19 \)
The denominator remains \( 7 \).
So, \( 2\frac{5}{7} = \frac{19}{7} \)

Answer:

s:

1. \(\boldsymbol{\frac{67}{9}}\)
2. \(\boldsymbol{\frac{41}{8}}\)
3. \(\boldsymbol{\frac{57}{10}}\)
4. \(\boldsymbol{\frac{19}{7}}\)