Question

1. $-9x + 1 = -80$
2. $-6 = \frac{n}{2} - 10$
3. $-2 = 2 + \frac{v}{4}$
4. $144 = -12(x + 5)$

Explanation:

Step1: Isolate the term with $x$

Subtract 1 from both sides:
$-9x + 1 - 1 = -80 - 1$
$-9x = -81$

Step2: Solve for $x$

Divide both sides by $-9$:
$x = \frac{-81}{-9}$
$x = 9$

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Step1: Isolate the term with $n$

Add 10 to both sides:
$-6 + 10 = \frac{n}{2} - 10 + 10$
$4 = \frac{n}{2}$

Step2: Solve for $n$

Multiply both sides by 2:
$n = 4 \times 2$
$n = 8$

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Step1: Isolate the term with $v$

Subtract 2 from both sides:
$-2 - 2 = 2 + \frac{v}{4} - 2$
$-4 = \frac{v}{4}$

Step2: Solve for $v$

Multiply both sides by 4:
$v = -4 \times 4$
$v = -16$

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Step1: Isolate the parentheses

Divide both sides by $-12$:
$\frac{144}{-12} = \frac{-12(x+5)}{-12}$
$-12 = x + 5$

Step2: Solve for $x$

Subtract 5 from both sides:
$x = -12 - 5$
$x = -17$

Answer:

1. $x = 9$
2. $n = 8$
3. $v = -16$
4. $x = -17$