QUESTION IMAGE
Question
- $4y > 28$ or $y + 1 < 4$
- $\frac{x}{7} < 1$ or $2x > 16$
- $\frac{p}{10} < -1$ or $p - 5 > 2$
- $5x > 45$ or $-6x \geq 12$
- $-10m \geq -30$ and $m - 10 \geq -8$
- $3n > -30$ and $\frac{n}{2} < 4$
- $0 \leq \frac{n}{4} < 2$
- $-10x \geq 100$ or $x - 3 \geq 4$
Let's solve problem 9: \( 4y > 28 \) or \( y + 1 < 4 \)
Step 1: Solve \( 4y > 28 \)
Divide both sides by 4:
\( \frac{4y}{4} > \frac{28}{4} \)
\( y > 7 \)
Step 2: Solve \( y + 1 < 4 \)
Subtract 1 from both sides:
\( y + 1 - 1 < 4 - 1 \)
\( y < 3 \)
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The solution is \( y > 7 \) or \( y < 3 \) (all real numbers less than 3 or greater than 7).