Question

c(-1,7) d(4,4) e(1,2) j(-2,5) k(2,6) l(1,7) m(-3, -6,7 -3,0 -1,5 -8,2) triangle abc with vertices a(0,7), b(7,3), and c(1,4): (x,y)→(x - 3,y - 4) a(-3,3) b(4,-1) c(-2,0) t maps each preimage to its image in coordinate notation rule: (x,y)→(__,__)

Explanation:

Step1: Analyze the change in \(x\) - coordinate

Take a point, say \(Q(0,2)\) and \(Q'(0, - 2)\). The \(x\) - coordinate remains the same (\(0-0 = 0\)), but for \(P(-2,3)\) and \(P'(-2,1)\), the \(y\) - coordinate changes.
Let's use the general formula \((x,y)\to(x,y + k)\).
For \(Q(0,2)\) and \(Q'(0,-2)\), we have \(2 + k=-2\), so \(k=-4\).

Step2: Verify with another point

Take \(R(-4,0)\) and \(R'(-4,-4)\). Using the rule \((x,y)\to(x,y - 4)\)
For \(x=-4\), \(y = 0\), applying the rule \((-4,0)\to(-4,0 - 4)=(-4,-4)\)

Answer:

\((x,y)\to(x,y - 4)\)