QUESTION IMAGE
Question
09/03 - segment bisector practice l (updated)
possible points: 5.4
using the figure, answer the following questions.
- name the mid - point of aq.
- what is the coordinate of the mid - point of ws?
- what is the coordinate of the mid - point of sb?
- the coordinate of the mid - point ar is - 3. what is the coordinate point of r?
- the coordinate of the mid - point of st is 4. what is the coordinate of point t?
Step1: Recall mid - point formula
The mid - point formula for two points with coordinates $x_1$ and $x_2$ on a number line is $M=\frac{x_1 + x_2}{2}$.
Step2: Find mid - point of $\overline{AQ}$
The coordinate of $A$ is $0$ and the coordinate of $Q$ is $4$. Using the mid - point formula $M=\frac{0 + 4}{2}=2$, so the mid - point is $S$.
Step3: Find mid - point of $\overline{WS}$
The coordinate of $W$ is $-8$ and the coordinate of $S$ is $2$. Then $M=\frac{-8 + 2}{2}=\frac{-6}{2}=-3$.
Step4: Find mid - point of $\overline{SB}$
The coordinate of $S$ is $2$ and the coordinate of $B$ is $8$. So $M=\frac{2+8}{2}=\frac{10}{2}=5$.
Step5: Find coordinate of $R$ given mid - point of $\overline{AR}$
Let the coordinate of $R$ be $x$. The coordinate of $A$ is $0$ and the mid - point of $\overline{AR}$ is $-3$. Using the mid - point formula $\frac{0 + x}{2}=-3$. Multiply both sides by $2$: $0 + x=-6$, so $x=-6$.
Step6: Find coordinate of $T$ given mid - point of $\overline{ST}$
Let the coordinate of $T$ be $y$. The coordinate of $S$ is $2$ and the mid - point of $\overline{ST}$ is $4$. Using the mid - point formula $\frac{2 + y}{2}=4$. Multiply both sides by $2$: $2 + y = 8$, then $y=6$.
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- $S$
- $-3$
- $5$
- $-6$
- $6$