Question

you set up a dialysis tubing experiment following the figure below. after submerging the dialysis tubing into the liquid in the beaker for 15 minutes,what color would the inside of the dialysis tubing, and what color would the beaker be? inside the beaker: iodine solution dialysis tubing inside the dialysis tubing: starch solution the liquid in the dialysis tube would have yellow-brown inside, and the liquid in the beaker would be blue-black. the liquid in the dialysis tube would have blue-black inside, and the liquid in the beaker would be yellow-brown. the liquid in the dialysis tube would have blue inside, and the liquid in the beaker would be orange. the liquid in the dialysis tube would have yellow-brown inside, and the liquid in the beaker would be yellow-brown. the liquid in the dialysis tube would have blue-black inside, and the liquid in the beaker would be blue-black. the liquid in the dialysis tube would have orange inside, and the liquid in the beaker would be blue.

Explanation:

Dialysis tubing is semi - permeable. Iodine molecules are small enough to pass through the dialysis tubing. Starch molecules are too large to pass through. Iodine reacts with starch to form a blue - black complex. The iodine solution in the beaker is yellow - brown. When iodine diffuses into the dialysis tubing (which has starch), it will turn the inside of the dialysis tubing blue - black. The starch cannot come out of the tubing, so the beaker solution remains yellow - brown (the color of iodine solution).

Answer:

The liquid in the dialysis tube would have blue - black inside, and the liquid in the beaker would be yellow - brown.