Question

you are pushing your two friends in separate swings. both friends have the same mass. if you push friend b with twice as much force as friend a, who will have a greater acceleration?
friend a
they will have the same acceleration
there is not enough information to determine who will have a greater acceleration.
friend b
question #2
what amount of force must be applied to a car with a mass of 1500 kg to accelerate it at a rate of 5.0 m/s²?
300 n
7,500 n
0.0033 n
33 n

Explanation:

Step1: Recall Newton's second - law

$F = ma$, where $F$ is force, $m$ is mass and $a$ is acceleration.

Step2: Analyze the first question

Let the force on friend A be $F_A$ and on friend B be $F_B = 2F_A$, and mass of both $m_A=m_B = m$. From $a=\frac{F}{m}$, for friend A, $a_A=\frac{F_A}{m}$, for friend B, $a_B=\frac{F_B}{m}=\frac{2F_A}{m}=2a_A$. So friend B has a greater acceleration.

Step3: Solve the second question

Given $m = 1500$ kg and $a=5.0$ m/s². Using $F = ma$, we substitute the values: $F=1500\times5.0 = 7500$ N.

Answer:

For the first question: D. Friend B
For the second question: B. 7,500 N