Question

write the balanced dissociation equation for solid calcium phosphate in aqueous solution. if it does not dissociate, simply write only nr. be sure to include the proper phases for all species within the reaction.
ca₃(po₄)₂(s)→3ca(aq)+2po₄(aq)

Explanation:

Step1: Identify the reactant and products

The reactant is \(Ca_3(PO_4)_2(s)\) and the products are \(Ca^{2 +}(aq)\) and \(PO_4^{3 -}(aq)\) based on the dissociation concept.

Step2: Balance the ions

For calcium: In \(Ca_3(PO_4)_2\), there are 3 calcium atoms. So we write \(3Ca^{2+}(aq)\) to balance calcium. For phosphate: In \(Ca_3(PO_4)_2\), there are 2 phosphate \((PO_4^{3 -})\) groups. So we write \(2PO_4^{3 -}(aq)\) to balance phosphate.

Answer:

\(Ca_3(PO_4)_2(s)
ightarrow3Ca^{2 +}(aq)+2PO_4^{3 -}(aq)\)