Question

6 woody is heterozygous for his finger length (ff), but his girlfriend bo peep has short fingers (ff). select all the possible genotypes and phenotypes for their children. make sure you do the punnett square for this in sketchschool and put screenshot in the google slide in the google classroom. a ff b ff c ff

Explanation:

Step1: Determine Parent Genotypes

Woody: \( Ff \), Bo Peep: \( ff \)

Step2: Set Up Punnett Square

	\( F \)	\( f \)
\( f \)	\( Ff \)	\( ff \)

Step3: Analyze Offspring Genotypes

From the square, possible genotypes: \( Ff \) (50%) and \( ff \) (50%). \( FF \) is not possible.

Step4: Analyze Phenotypes

• \( Ff \): Dominant (long fingers, assuming \( F \) is dominant)
• \( ff \): Recessive (short fingers)

Answer:

Possible Genotypes: A. \( ff \), C. \( Ff \)
Possible Phenotypes: \( ff \) (short fingers), \( Ff \) (long fingers)