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Question
which rule explains why these triangles are congruent? sss aas asa sas these triangles cannot be proven congruent.
Brief Explanations
- First, identify the vertical angles at \( V \): \( \angle XVW \) and \( \angle ZVY \) are vertical angles, so they are equal.
- Then, look at the marked angles: \( \angle X \cong \angle Y \) (double arcs) and \( \angle W \cong \angle Z \) (single arcs). Wait, no, actually, let's re - examine. Wait, the triangles are \( \triangle XVW \) and \( \triangle YVZ \)? Wait, no, the vertices: \( X, V, W \) and \( Z, V, Y \). The angles: \( \angle X \) and \( \angle Y \) (double arcs), \( \angle W \) and \( \angle Z \) (single arcs), and the vertical angles at \( V \) ( \( \angle XVW=\angle ZVY \) ). So we have two angles and a non - included side? Wait, no, AAS (Angle - Angle - Side) states that if two angles and a non - included side of one triangle are congruent to the corresponding two angles and non - included side of another triangle, the triangles are congruent. Let's check:
- \( \angle X\cong\angle Y \) (given by the double arcs).
- \( \angle XVW\cong\angle ZVY \) (vertical angles).
- The side between? Wait, no, AAS: two angles and a side that is not between them. Wait, actually, in \( \triangle XVW \) and \( \triangle YVZ \), we have \( \angle X\cong\angle Y \), \( \angle XVW\cong\angle ZVY \), and the side \( VW \) and \( VZ \)? No, wait, the vertical angles are at \( V \), so the sides: the side opposite to one of the angles. Wait, maybe I made a mistake. Wait, let's list the congruent parts:
- \( \angle X=\angle Y \) (marked with two arcs).
- \( \angle W=\angle Z \) (marked with one arc).
- The vertical angles \( \angle XVW=\angle ZVY \). Wait, no, actually, the triangles are \( \triangle XW V \) and \( \triangle ZY V \). Wait, the vertical angles are \( \angle XVW \) and \( \angle ZVY \). So we have two angles ( \( \angle X \) and \( \angle W \) in \( \triangle XVW \), and \( \angle Y \) and \( \angle Z \) in \( \triangle ZVY \)) and the included side? No, AAS: if two angles and a non - included side are congruent. Wait, let's recall the AAS criterion: AAS (Angle - Angle - Side) means that two angles and a side that is not between them are congruent. In this case, we have \( \angle X\cong\angle Y \), \( \angle XVW\cong\angle ZVY \) (vertical angles), and the side \( VW \) and \( VZ \)? No, wait, the side opposite to one of the angles. Wait, actually, the correct way: in \( \triangle XVW \) and \( \triangle YVZ \), we have:
- \( \angle X\cong\angle Y \) (given by the markings).
- \( \angle XVW\cong\angle ZVY \) (vertical angles, so congruent).
- The side \( VW \) and \( VZ \)? No, wait, the side between \( \angle X \) and \( \angle XVW \) is \( XV \), and between \( \angle Y \) and \( \angle ZVY \) is \( YV \)? No, maybe I messed up the triangles. Wait, the triangles are \( \triangle XWV \) and \( \triangle ZYV \). Wait, the angles: \( \angle X \) and \( \angle Y \) (double arcs), \( \angle W \) and \( \angle Z \) (single arcs), and the vertical angles at \( V \). So we have two angles and a side? Wait, AAS: two angles and a non - included side. So if we have two angles (e.g., \( \angle X \) and \( \angle W \)) and the side \( XW \), but no, the vertical angles are at \( V \). Wait, actually, the correct congruence rule here is AAS. Because we have two angles ( \( \angle X\cong\angle Y \), \( \angle W\cong\angle Z \)) and the side \( VW \cong VZ \)? No, wait, the vertical angles are equal, and two other angles. Wait, let's start over.
- Vertical angles: \( \angle XVW=\angle ZVY \) (vertical angles are congruent).
- Given \( \angle X=\angle Y \) (double arcs) and \( \angle W…
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B. AAS