Question

which number equals $i^{8}$? -i i 1 -1

Explanation:

Step1: Recall the property of $i$

We know that $i = \sqrt{-1}$, $i^2=-1$, $i^3 = i^2\times i=-i$, $i^4=(i^2)^2=(-1)^2 = 1$.

Step2: Rewrite $i^8$

Since $i^8=(i^4)^2$.

Step3: Substitute the value of $i^4$

Substitute $i^4 = 1$ into $(i^4)^2$, we get $(i^4)^2=1^2 = 1$.

Answer:

C. 1