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which of the following descriptions is true about the punnett diagram b…

Question

which of the following descriptions is true about the punnett diagram below? aas.1a note: h - short hair h - no hair? h h hh hh hh hh a the parent genotype will be shown in all of the offspring b the missing parent is homozygous c this is a cross of two heterozygous parents d there is a phenotypic ratio of 1:2:1 for offspring

Explanation:

Brief Explanations

To determine the correct answer, analyze each option:

  • Option A: Offspring have genotypes \( HH \), \( Hh \), and \( hh \), so the parent genotype won't be the same in all offspring. Eliminate A.
  • Option B: One parent is \( Hh \) (from the top row: \( H \) and \( h \)) and the other parent (missing) must be \( Hh \) to get the given Punnett square? No, wait—wait, the top row parents: one is \( H \) (from the first column top: \( H \)) and the other? Wait, the Punnett square has columns from one parent (let's say the horizontal parent) and rows from the vertical parent. The vertical parent's alleles are \( H \) (top) and \( h \) (bottom, since the bottom row has \( h \) in the vertical parent's allele? Wait, no—let's re-examine. The Punnett square cells are \( HH \), \( Hh \), \( Hh \), \( hh \)? Wait, no, the image shows the Punnett square with top row (horizontal parent) as \( H \) and \( h \)? Wait, the left column vertical parent is \( H \) (top) and \( h \) (bottom)? Wait, no, the given Punnett square has:

Top row (horizontal parent's alleles? No, Punnett square columns are one parent's gametes, rows the other's. Let's list the offspring: \( HH \), \( Hh \), \( Hh \), \( hh \)? Wait, no, the image shows the Punnett square with two cells in the top row: \( HH \) and \( Hh \), and bottom row: \( Hh \) and \( hh \). Wait, actually, the vertical parent (rows) has alleles \( H \) (top row) and \( h \) (bottom row), and the horizontal parent (columns) has alleles \( H \) (left column) and \( h \) (right column)? No, wait, the top - left cell is \( HH \), top - right is \( Hh \), bottom - left is \( Hh \), bottom - right is \( hh \). Wait, no, the original image: the top row of the Punnett square (columns) has one parent's alleles: let's say the horizontal parent is \( Hh \) (alleles \( H \) and \( h \)) and the vertical parent is \( Hh \) (alleles \( H \) and \( h \))? But then the Punnett square would be \( HH \), \( Hh \), \( Hh \), \( hh \), which matches the cells? Wait, no, the cells shown are \( HH \), \( Hh \), \( Hh \), \( hh \)? Wait, the image's Punnett square: first row (top) cells: \( HH \) (left), \( Hh \) (right); second row (bottom) cells: \( Hh \) (left), \( hh \) (right). So the vertical parent (rows) has alleles \( H \) (top row) and \( h \) (bottom row), and the horizontal parent (columns) has alleles \( H \) (left column) and \( h \) (right column)? No, that would make the horizontal parent \( Hh \) (alleles \( H \) and \( h \)) and vertical parent \( Hh \) (alleles \( H \) and \( h \)). But option B says "the missing parent is homozygous"—is that true? Wait, no, maybe I made a mistake. Wait, let's check the offspring genotypes: \( HH \), \( Hh \), \( Hh \), \( hh \). The phenotypic ratio for hair: \( H \) is short hair, \( h \) is no hair? Wait, note says \( H \) - short hair, \( h \) - no hair. So \( HH \) and \( Hh \) have short hair, \( hh \) has no hair. The phenotypic ratio would be 3:1 (short:no hair), but option D says 1:2:1, which is genotypic ratio. Wait, option D: "there is a phenotypic ratio of 1:2:1 for offspring"—no, phenotypic ratio for \( H \) (dominant) and \( h \) (recessive) would be 3:1 (short:no hair), but genotypic ratio is 1:2:1 (\( HH:Hh:hh \)). Wait, maybe the note has a typo, or maybe \( H \) is dominant, \( h \) is recessive, so genotypic ratio \( 1:2:1 \) ( \( HH:Hh:hh \) ), which is what option D says? Wait, no, let's re - evaluate the options:

  • Option C: "this is a cross of two heterozygous parents"—if both parents are \( Hh \), the Punnett square would be \( HH \), \( Hh \), \( Hh \…

Answer:

D. there is a phenotypic ratio of 1:2:1 for offspring