QUESTION IMAGE
Question
whether it has no solutions, exactly one solution, or infinitely many solutions. if an equation has one solution, solve to find the value that makes the statement true. explain why you chose no solution or infinitely many solutions.
2
a. $\frac{1}{4}(12 - 4x) = 3 - x$
b. $x - 3 = 3 - x$
c. $x - 3 = 3 + x$
3.
a. $-5x - 3x + 2 = -8x + 2$
b. $-5x - 3x - 4 = -8x + 2$
c. $-5x - 4x - 2 = -8x + 2$
4.
a. $4(2x - 2) + 2 = 4(x - 2)$
b. $4x + 2(2x - 3) = 8(x - 1)$
c. $4x + 2(2x - 3) = 4(2x - 2) + 2$
5.
a. $x - 3(2 - 3x) = 2(5x + 3)$
b. $x - 3(2 + 3x) = 2(5x - 3)$
c. $x - 3(2 - 3x) = 2(5x - 3)$
2a Solution:
Step1: Distribute the fraction
Multiply \(\frac{1}{4}\) with each term inside the parentheses: \(\frac{1}{4}(12 - 4x)=\frac{12}{4}-\frac{4x}{4}=3 - x\).
Step2: Analyze the equation
After simplifying, we get \(3 - x = 3 - x\). This is an identity, meaning it holds true for all real values of \(x\).
Step1: Rearrange terms
Add \(x\) to both sides and add \(3\) to both sides: \(x + x=3 + 3\).
Step2: Solve for \(x\)
Simplify to get \(2x = 6\), then divide both sides by \(2\): \(x = 3\).
Step1: Rearrange terms
Subtract \(x\) from both sides: \(x - x-3 = 3 + x - x\).
Step2: Analyze the result
Simplifying gives \(-3 = 3\), which is a false statement.
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The equation \(\frac{1}{4}(12 - 4x)=3 - x\) has infinitely many solutions because simplifying it results in an identity (\(3 - x = 3 - x\)) that is true for all \(x\).