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3. when the mean is greater than the median, the data is... a. skewed l…

Question

  1. when the mean is greater than the median, the data is...

a. skewed left c. bell - shaped / symmetrical
b. skewed right d. uniform

  1. the following represents a sample of raw data.

18 21 15 13
find the following.
mean: median:
mode: midrange:
range: what is the deviation for the value of 13?

Explanation:

Step1: Calculate the mean

The mean $\bar{x}$ of a set of data $x_1,x_2,\cdots,x_n$ is given by $\bar{x}=\frac{\sum_{i = 1}^{n}x_i}{n}$. Here, $n = 4$, $x_1=18$, $x_2 = 21$, $x_3=15$, $x_4=13$. Then $\sum_{i=1}^{4}x_i=18 + 21+15 + 13=67$. So, $\bar{x}=\frac{67}{4}=16.75$.

Step2: Calculate the median

First, order the data: $13,15,18,21$. Since $n = 4$ (even), the median $M=\frac{x_{\frac{n}{2}}+x_{\frac{n}{2}+1}}{2}$. Here, $x_{2}=15$ and $x_{3}=18$. So, $M=\frac{15 + 18}{2}=16.5$.

Step3: Calculate the mode

The mode is the most frequently - occurring value. In the data set $\{13,15,18,21\}$, each value occurs exactly once. So, there is no mode.

Step4: Calculate the mid - range

The mid - range $MR=\frac{\text{Min}+\text{Max}}{2}$. Here, $\text{Min}=13$ and $\text{Max}=21$. So, $MR=\frac{13 + 21}{2}=17$.

Step5: Calculate the range

The range $R=\text{Max}-\text{Min}$. So, $R=21-13 = 8$.

Step6: Calculate the deviation for the value of 13

The deviation of a value $x$ from the mean $\bar{x}$ is $x-\bar{x}$. For $x = 13$, the deviation is $13-16.75=-3.75$.

Answer:

Mean: $16.75$
Median: $16.5$
Mode: No mode
Midrange: $17$
Range: $8$
Deviation for $13$: $- 3.75$