Question

a wheelbarrow is used to lift a 200 lb load. the length from the wheel axle to the center of the load is 2 ft. the length from the wheel and axle to the effort is 5 ft. what is the ideal mechanical advantage of the system? ima = 5.20 ima = 3.40 ima = 6.30 ima = 2.50

Explanation:

Step1: Recall the formula for IMA of a lever

The formula for the ideal mechanical advantage (\(IMA\)) of a lever is \(IMA=\frac{d_{e}}{d_{r}}\), where \(d_{e}\) is the effort - distance and \(d_{r}\) is the resistance - distance.

Step2: Identify the values of \(d_{e}\) and \(d_{r}\)

Given that \(d_{e} = 5\space ft\) (length from the wheel and axle to the effort) and \(d_{r}=2\space ft\) (length from the wheel axle to the center of the load).

Step3: Calculate the IMA

Substitute the values into the formula: \(IMA=\frac{5}{2}=2.5\)

Answer:

IMA = 2.50