Question

1. what are the zeros of ( x^2 + 4x - 12 = 0 )?

a. ( x = 2 ) and ( x = -6 )
b. ( x = -2 ) and ( x = 6 )
c. ( x = 3 ) and ( x = -4 )
d. ( x = -3 ) and ( x = 4 )

Explanation:

Step1: Factor the quadratic equation

To find the zeros of \(x^2 + 4x - 12 = 0\), we factor the quadratic. We need two numbers that multiply to \(-12\) and add to \(4\). The numbers are \(6\) and \(-2\), so the equation factors as \((x + 6)(x - 2)=0\).

Step2: Solve for x

Set each factor equal to zero:

• For \(x + 6 = 0\), we get \(x=-6\).
• For \(x - 2 = 0\), we get \(x = 2\).

Answer:

A. \(x = 2\) and \(x = -6\)