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Question
what is the solution to \\(\log_{4} 8x = 3\\)?
\\(x = \frac{3}{8}\\)
\\(x = \frac{3}{2}\\)
\\(x = 2\\)
\\(x = 8\\)
Convert to exponential form
$$
\log_{4}(8x) = 3 \implies 8x = 4^3
$$
Simplify and solve for x
$$
LATEXBLOCK0
$$
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- (A) \(x = \frac{3}{8}\)
- (B) \(x = \frac{3}{2}\)
- (C) \(x = 2\)
- (D) \(x = 8\) (Correct answer)