QUESTION IMAGE
Question
what is the perimeter of δfgh? write your answer as an integer or as a decimal rounded to the neares
perimeter = units
Step1: Identify coordinates of points
From the graph, we can see the coordinates:
- \( F(-8, -4) \)
- \( G(7, -9) \) (Wait, looking at the grid, G is at (7, -9)? Wait, no, looking at the x-axis, G is at x=7? Wait, no, the grid lines: let's check again. Wait, H is at (7,7)? Wait, no, the y-axis: H is at (7,7)? Wait, no, the grid: each square is 1 unit. Let's re-express:
Wait, F is at (-8, -4), G is at (7, -9)? No, wait, looking at the graph, G is at (7, -9)? Wait, no, the vertical line from G to H: H is at (7,7) and G is at (7, -9)? Wait, no, the y-coordinate of H is 7 (since it's at y=7), G is at y=-9? Wait, no, the grid: from y=-10 to y=10, each line is 1 unit. So H is at (7,7), G is at (7, -9)? Wait, no, the distance between H and G: from y=7 to y=-9, that's 16 units? Wait, no, let's check the coordinates properly.
Wait, F is at (-8, -4), G is at (7, -9)? No, wait, looking at the x-axis: F is at x=-8, y=-4. G is at x=7, y=-9? Wait, no, the point G is at (7, -9)? Wait, no, the vertical line from G to H: H is at (7,7) (since y=7), G is at (7, -9)? Then the length of GH is |7 - (-9)| = 16? Wait, no, that can't be. Wait, maybe I misread the coordinates. Let's look again:
Wait, F is at (-8, -4), G is at (7, -9)? No, the x-coordinate of G: looking at the grid, G is at x=7 (since it's 7 units to the right of the origin), y=-9? H is at x=7, y=7. So GH is vertical, length is 7 - (-9) = 16? Wait, no, 7 - (-9) = 16? Wait, 7 - (-9) = 16? Yes, because from y=-9 to y=7 is 16 units (7 - (-9) = 16). Then FG: distance between F(-8, -4) and G(7, -9). Using distance formula: \( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \). So \( x_2 - x_1 = 7 - (-8) = 15 \), \( y_2 - y_1 = -9 - (-4) = -5 \). So \( FG = \sqrt{15^2 + (-5)^2} = \sqrt{225 + 25} = \sqrt{250} \approx 15.81 \). Then FH: distance between F(-8, -4) and H(7,7). \( x_2 - x_1 = 7 - (-8) = 15 \), \( y_2 - y_1 = 7 - (-4) = 11 \). So \( FH = \sqrt{15^2 + 11^2} = \sqrt{225 + 121} = \sqrt{346} \approx 18.60 \). Wait, that can't be right. Wait, maybe I misread the coordinates. Let's check again.
Wait, maybe F is at (-8, -4), G is at (7, -9)? No, maybe G is at (7, -9)? Wait, no, the graph: F is at (-8, -4), G is at (7, -9)? Wait, no, the vertical line from G to H: H is at (7,7), G is at (7, -9). Then GH is 16 units. Then FG: from (-8, -4) to (7, -9): horizontal distance 15, vertical distance 5 (since -4 to -9 is 5 units down). So \( FG = \sqrt{15^2 + 5^2} = \sqrt{225 + 25} = \sqrt{250} \approx 15.81 \). FH: from (-8, -4) to (7,7): horizontal distance 15, vertical distance 11 (from -4 to 7 is 11 units up). So \( FH = \sqrt{15^2 + 11^2} = \sqrt{225 + 121} = \sqrt{346} \approx 18.60 \). Then perimeter is \( 16 + 15.81 + 18.60 \approx 50.41 \). Wait, that seems too big. Maybe I misread the coordinates. Let's check again.
Wait, maybe F is at (-8, -4), G is at (7, -9)? No, maybe G is at (7, -9)? Wait, no, the grid: each square is 1 unit. Let's check the x-coordinates: F is at x=-8, G is at x=7 (since from x=-8 to x=7 is 15 units). Y-coordinates: F is at y=-4, G is at y=-9 (so 5 units down), H is at y=7 (so from G at y=-9 to H at y=7 is 16 units up). So GH is 16. FG: distance between (-8, -4) and (7, -9): \( \sqrt{(7 - (-8))^2 + (-9 - (-4))^2} = \sqrt{15^2 + (-5)^2} = \sqrt{225 + 25} = \sqrt{250} \approx 15.81 \). FH: distance between (-8, -4) and (7,7): \( \sqrt{(7 - (-8))^2 + (7 - (-4))^2} = \sqrt{15^2 + 11^2} = \sqrt{225 + 121} = \sqrt{346} \approx 18.60 \). Then perimeter is 16 + 15.81 + 18.60 ≈ 50.41. But that seems off. Wait, maybe I made a mistake in the coordinates. Let's check the graph again.…
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\( 50.4 \) (rounded to the nearest tenth)