Question

what is the correct electron configuration for tellurium? xe 5s², 5d¹⁰, 5p⁴ ar 5s², 4d¹⁰, 5p⁴ kr 5s², 4d¹⁰, 5p⁴ kr 5s², 5d¹⁰, 5p⁴

Explanation:

Tellurium has an atomic number of 52. Krypton (\([Kr]\)) has an atomic number of 36. After \([Kr]\), the electron - filling order is \(5s\), then \(4d\), and then \(5p\). The \(4d\) sub - shell is filled before the \(5p\) sub - shell. The number of electrons after \([Kr]\) in tellurium is \(52 - 36=16\). \(2\) electrons go to \(5s\), \(10\) electrons go to \(4d\), and \(4\) electrons go to \(5p\).

Answer:

\([Kr]5s^{2},4d^{10},5p^{4}\) (the third option)