Question

what are the x -intercepts of $y = x^2 - 4$?
x = 4, -4
x = 0, 4
x = 2, -2
x = 0, -4

Explanation:

Step1: Recall x-intercept definition

To find x-intercepts, set \( y = 0 \) in the equation \( y = x^2 - 4 \). So we solve \( 0 = x^2 - 4 \).

Step2: Solve the equation

Rewrite the equation as \( x^2 = 4 \). Taking square roots on both sides, we get \( x=\pm\sqrt{4}=\pm 2 \). So the x - intercepts are \( x = 2 \) and \( x=-2 \).

Answer:

C. \( x = 2, -2 \) (assuming the third option is labeled C, with text \( x = 2, -2 \))